Integrand size = 19, antiderivative size = 93 \[ \int \cot ^6(c+d x) (a+b \tan (c+d x)) \, dx=-a x-\frac {a \cot (c+d x)}{d}+\frac {b \cot ^2(c+d x)}{2 d}+\frac {a \cot ^3(c+d x)}{3 d}-\frac {b \cot ^4(c+d x)}{4 d}-\frac {a \cot ^5(c+d x)}{5 d}+\frac {b \log (\sin (c+d x))}{d} \]
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Time = 0.18 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {3610, 3612, 3556} \[ \int \cot ^6(c+d x) (a+b \tan (c+d x)) \, dx=-\frac {a \cot ^5(c+d x)}{5 d}+\frac {a \cot ^3(c+d x)}{3 d}-\frac {a \cot (c+d x)}{d}-a x-\frac {b \cot ^4(c+d x)}{4 d}+\frac {b \cot ^2(c+d x)}{2 d}+\frac {b \log (\sin (c+d x))}{d} \]
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Rule 3556
Rule 3610
Rule 3612
Rubi steps \begin{align*} \text {integral}& = -\frac {a \cot ^5(c+d x)}{5 d}+\int \cot ^5(c+d x) (b-a \tan (c+d x)) \, dx \\ & = -\frac {b \cot ^4(c+d x)}{4 d}-\frac {a \cot ^5(c+d x)}{5 d}+\int \cot ^4(c+d x) (-a-b \tan (c+d x)) \, dx \\ & = \frac {a \cot ^3(c+d x)}{3 d}-\frac {b \cot ^4(c+d x)}{4 d}-\frac {a \cot ^5(c+d x)}{5 d}+\int \cot ^3(c+d x) (-b+a \tan (c+d x)) \, dx \\ & = \frac {b \cot ^2(c+d x)}{2 d}+\frac {a \cot ^3(c+d x)}{3 d}-\frac {b \cot ^4(c+d x)}{4 d}-\frac {a \cot ^5(c+d x)}{5 d}+\int \cot ^2(c+d x) (a+b \tan (c+d x)) \, dx \\ & = -\frac {a \cot (c+d x)}{d}+\frac {b \cot ^2(c+d x)}{2 d}+\frac {a \cot ^3(c+d x)}{3 d}-\frac {b \cot ^4(c+d x)}{4 d}-\frac {a \cot ^5(c+d x)}{5 d}+\int \cot (c+d x) (b-a \tan (c+d x)) \, dx \\ & = -a x-\frac {a \cot (c+d x)}{d}+\frac {b \cot ^2(c+d x)}{2 d}+\frac {a \cot ^3(c+d x)}{3 d}-\frac {b \cot ^4(c+d x)}{4 d}-\frac {a \cot ^5(c+d x)}{5 d}+b \int \cot (c+d x) \, dx \\ & = -a x-\frac {a \cot (c+d x)}{d}+\frac {b \cot ^2(c+d x)}{2 d}+\frac {a \cot ^3(c+d x)}{3 d}-\frac {b \cot ^4(c+d x)}{4 d}-\frac {a \cot ^5(c+d x)}{5 d}+\frac {b \log (\sin (c+d x))}{d} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.05 (sec) , antiderivative size = 91, normalized size of antiderivative = 0.98 \[ \int \cot ^6(c+d x) (a+b \tan (c+d x)) \, dx=\frac {b \cot ^2(c+d x)}{2 d}-\frac {b \cot ^4(c+d x)}{4 d}-\frac {a \cot ^5(c+d x) \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},1,-\frac {3}{2},-\tan ^2(c+d x)\right )}{5 d}+\frac {b \log (\cos (c+d x))}{d}+\frac {b \log (\tan (c+d x))}{d} \]
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Time = 0.47 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.94
method | result | size |
parallelrisch | \(\frac {-12 \left (\cot ^{5}\left (d x +c \right )\right ) a -15 \left (\cot ^{4}\left (d x +c \right )\right ) b +20 \left (\cot ^{3}\left (d x +c \right )\right ) a +30 \left (\cot ^{2}\left (d x +c \right )\right ) b -60 a d x +60 b \ln \left (\tan \left (d x +c \right )\right )-30 b \ln \left (\sec ^{2}\left (d x +c \right )\right )-60 \cot \left (d x +c \right ) a}{60 d}\) | \(87\) |
derivativedivides | \(\frac {-\frac {a}{5 \tan \left (d x +c \right )^{5}}-\frac {a}{\tan \left (d x +c \right )}-\frac {b}{4 \tan \left (d x +c \right )^{4}}+b \ln \left (\tan \left (d x +c \right )\right )+\frac {a}{3 \tan \left (d x +c \right )^{3}}+\frac {b}{2 \tan \left (d x +c \right )^{2}}-\frac {b \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}-a \arctan \left (\tan \left (d x +c \right )\right )}{d}\) | \(94\) |
default | \(\frac {-\frac {a}{5 \tan \left (d x +c \right )^{5}}-\frac {a}{\tan \left (d x +c \right )}-\frac {b}{4 \tan \left (d x +c \right )^{4}}+b \ln \left (\tan \left (d x +c \right )\right )+\frac {a}{3 \tan \left (d x +c \right )^{3}}+\frac {b}{2 \tan \left (d x +c \right )^{2}}-\frac {b \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}-a \arctan \left (\tan \left (d x +c \right )\right )}{d}\) | \(94\) |
norman | \(\frac {-\frac {a}{5 d}-a x \left (\tan ^{5}\left (d x +c \right )\right )+\frac {a \left (\tan ^{2}\left (d x +c \right )\right )}{3 d}-\frac {a \left (\tan ^{4}\left (d x +c \right )\right )}{d}-\frac {b \tan \left (d x +c \right )}{4 d}+\frac {b \left (\tan ^{3}\left (d x +c \right )\right )}{2 d}}{\tan \left (d x +c \right )^{5}}+\frac {b \ln \left (\tan \left (d x +c \right )\right )}{d}-\frac {b \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2 d}\) | \(113\) |
risch | \(-i b x -a x -\frac {2 i b c}{d}-\frac {2 \left (45 i a \,{\mathrm e}^{8 i \left (d x +c \right )}+30 b \,{\mathrm e}^{8 i \left (d x +c \right )}-90 i a \,{\mathrm e}^{6 i \left (d x +c \right )}-60 b \,{\mathrm e}^{6 i \left (d x +c \right )}+140 i a \,{\mathrm e}^{4 i \left (d x +c \right )}+60 b \,{\mathrm e}^{4 i \left (d x +c \right )}-70 i a \,{\mathrm e}^{2 i \left (d x +c \right )}-30 b \,{\mathrm e}^{2 i \left (d x +c \right )}+23 i a \right )}{15 d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{5}}+\frac {b \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d}\) | \(159\) |
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Time = 0.24 (sec) , antiderivative size = 111, normalized size of antiderivative = 1.19 \[ \int \cot ^6(c+d x) (a+b \tan (c+d x)) \, dx=\frac {30 \, b \log \left (\frac {\tan \left (d x + c\right )^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) \tan \left (d x + c\right )^{5} - 15 \, {\left (4 \, a d x - 3 \, b\right )} \tan \left (d x + c\right )^{5} - 60 \, a \tan \left (d x + c\right )^{4} + 30 \, b \tan \left (d x + c\right )^{3} + 20 \, a \tan \left (d x + c\right )^{2} - 15 \, b \tan \left (d x + c\right ) - 12 \, a}{60 \, d \tan \left (d x + c\right )^{5}} \]
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Time = 1.36 (sec) , antiderivative size = 121, normalized size of antiderivative = 1.30 \[ \int \cot ^6(c+d x) (a+b \tan (c+d x)) \, dx=\begin {cases} \tilde {\infty } a x & \text {for}\: c = 0 \wedge d = 0 \\x \left (a + b \tan {\left (c \right )}\right ) \cot ^{6}{\left (c \right )} & \text {for}\: d = 0 \\\tilde {\infty } a x & \text {for}\: c = - d x \\- a x - \frac {a}{d \tan {\left (c + d x \right )}} + \frac {a}{3 d \tan ^{3}{\left (c + d x \right )}} - \frac {a}{5 d \tan ^{5}{\left (c + d x \right )}} - \frac {b \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 d} + \frac {b \log {\left (\tan {\left (c + d x \right )} \right )}}{d} + \frac {b}{2 d \tan ^{2}{\left (c + d x \right )}} - \frac {b}{4 d \tan ^{4}{\left (c + d x \right )}} & \text {otherwise} \end {cases} \]
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Time = 0.36 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.00 \[ \int \cot ^6(c+d x) (a+b \tan (c+d x)) \, dx=-\frac {60 \, {\left (d x + c\right )} a + 30 \, b \log \left (\tan \left (d x + c\right )^{2} + 1\right ) - 60 \, b \log \left (\tan \left (d x + c\right )\right ) + \frac {60 \, a \tan \left (d x + c\right )^{4} - 30 \, b \tan \left (d x + c\right )^{3} - 20 \, a \tan \left (d x + c\right )^{2} + 15 \, b \tan \left (d x + c\right ) + 12 \, a}{\tan \left (d x + c\right )^{5}}}{60 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 198 vs. \(2 (85) = 170\).
Time = 0.62 (sec) , antiderivative size = 198, normalized size of antiderivative = 2.13 \[ \int \cot ^6(c+d x) (a+b \tan (c+d x)) \, dx=\frac {6 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 15 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 70 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 180 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 960 \, {\left (d x + c\right )} a - 960 \, b \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right ) + 960 \, b \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right ) + 660 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - \frac {2192 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 660 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 180 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 70 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 15 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 6 \, a}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5}}}{960 \, d} \]
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Time = 4.96 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.25 \[ \int \cot ^6(c+d x) (a+b \tan (c+d x)) \, dx=\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )-\mathrm {i}\right )\,\left (-\frac {b}{2}+\frac {a\,1{}\mathrm {i}}{2}\right )}{d}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )\,\left (\frac {b}{2}+\frac {a\,1{}\mathrm {i}}{2}\right )}{d}+\frac {b\,\ln \left (\mathrm {tan}\left (c+d\,x\right )\right )}{d}-\frac {{\mathrm {cot}\left (c+d\,x\right )}^5\,\left (a\,{\mathrm {tan}\left (c+d\,x\right )}^4-\frac {b\,{\mathrm {tan}\left (c+d\,x\right )}^3}{2}-\frac {a\,{\mathrm {tan}\left (c+d\,x\right )}^2}{3}+\frac {b\,\mathrm {tan}\left (c+d\,x\right )}{4}+\frac {a}{5}\right )}{d} \]
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